x-10x^(1/2)=-25

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Solution for x-10x^(1/2)=-25 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

x-(10*x^(1/2)) = -25 // + 25

x-(10*x^(1/2))+25 = 0

x-10*x^(1/2)+25 = 0

t_1 = x^(1/2)

1*t_1^2-10*t_1^1+25 = 0

t_1^2-10*t_1+25 = 0

DELTA = (-10)^2-(1*4*25)

DELTA = 0

t_1 = 10/(1*2)

t_1 = 5 or t_1 = 5

t_1 = 5

x^(1/2)-5 = 0

1*x^(1/2) = 5 // : 1

x^(1/2) = 5

x^(1/2) = 5 // ^ 2

x = 25

t_1 = 5

x^(1/2)-5 = 0

1*x^(1/2) = 5 // : 1

x^(1/2) = 5

x^(1/2) = 5 // ^ 2

x = 25

x in { 25, 25 }

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